z^2+4Z+(4+2i)=0

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Solution for z^2+4Z+(4+2i)=0 equation:


Simplifying
z2 + 4Z + (4 + 2i) = 0

Remove parenthesis around (4 + 2i)
z2 + 4Z + 4 + 2i = 0

Reorder the terms:
4 + 4Z + 2i + z2 = 0

Solving
4 + 4Z + 2i + z2 = 0

Solving for variable 'Z'.

Move all terms containing Z to the left, all other terms to the right.

Add '-4' to each side of the equation.
4 + 4Z + 2i + -4 + z2 = 0 + -4

Reorder the terms:
4 + -4 + 4Z + 2i + z2 = 0 + -4

Combine like terms: 4 + -4 = 0
0 + 4Z + 2i + z2 = 0 + -4
4Z + 2i + z2 = 0 + -4

Combine like terms: 0 + -4 = -4
4Z + 2i + z2 = -4

Add '-2i' to each side of the equation.
4Z + 2i + -2i + z2 = -4 + -2i

Combine like terms: 2i + -2i = 0
4Z + 0 + z2 = -4 + -2i
4Z + z2 = -4 + -2i

Add '-1z2' to each side of the equation.
4Z + z2 + -1z2 = -4 + -2i + -1z2

Combine like terms: z2 + -1z2 = 0
4Z + 0 = -4 + -2i + -1z2
4Z = -4 + -2i + -1z2

Divide each side by '4'.
Z = -1 + -0.5i + -0.25z2

Simplifying
Z = -1 + -0.5i + -0.25z2

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